4x^2+1x+5=0

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Solution for 4x^2+1x+5=0 equation: 



4x^2+1x+5=0

We add all the numbers together, and all the variables

4x^2+x+5=0

a = 4; b = 1; c = +5;
Δ = b2-4ac
Δ = 12-4·4·5
Δ = -79
Delta is less than zero, so there is no solution for the equation

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